{
int n;
printf("\n Enter any number:");
scanf("%d", &n); dec2bin(n);
}
dec2bin(int n)
{
if(n == 0)
return ; else
{
dec2bin (n/2);
printf("%d", n%10);
}
}
Program to print binary equivalent of a decimal number Note MSP should print first and LSB last.
main()
{
int n;
printf("\n Enter any number:");
scanf("%d", &n); dec2bin(n);
}
dec2bin(int n)
{
if(n == 0)
return ; else
{
dec2bin (n/2);
printf("%d", n%10);
}
}
{
int n;
printf("\n Enter any number:");
scanf("%d", &n); dec2bin(n);
}
dec2bin(int n)
{
if(n == 0)
return ; else
{
dec2bin (n/2);
printf("%d", n%10);
}
}
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Hits!!!
..it will not work..
ReplyDelete...can you make a sample program that will input an integer and displays the binary equivalent?
ReplyDeletemake a sample that will input an integer and displays the binary equivalent ?
ReplyDeleteyes sure frind please mail me details to hellopankajin@rediff.com i will mail u solution...
ReplyDeletedec2bin(int n)
ReplyDelete{
if(n == 0)
return ; else
{
dec2bin (n/2);
printf("%d", n%2);
}
}
i think now its right
#include
ReplyDeletemain()
{
unsigned int num;
int i;
scanf("%u",&num);
for(i=0;i<32;i++)
printf("%d",(num<<i & 1<<31)?1:0);
}