C Program to get mean ,median ,mode




#include
#include
#include

float mean1(float[],int);
float median1(float[],int);
float mode1(float[],int);
double standarddeviation1(float[],int);

int main()
{
int i,n,choice;
float array[100],mean,median,mode;
double standarddeviation;
printf("Enter No of Elements\n");
scanf("%d",&n);
printf("Enter Elements\n");
for(i=0;i<=n;i++)
scanf("%f",&array[i]);
do
{
printf("\n\tEnter Choice\n\t1.Mean\n\t2.Median\n\t3.Mode\n\t4.Standard deviation\n\t5.Exit\n");
scanf("%d",&choice);
switch(choice)
{
case 1: mean=mean1(array,n);
printf("\n\tMean = %f\n",mean);
break;
case 2: median=median1(array,n);
printf("\n\tMedian = %f\n",median);
break;
case 3: mode=mode1(array,n);
printf("\n\tMode = %f\n",mode);
break;
case 4: standarddeviation=standarddeviation1(array,n);
printf("\n\tStandard deviation = %f\n",standarddeviation);
break;
case 5: break;
default:printf("Wrong Option");
break;
}
}while(choice!=5);
getch();
return 0;
}

float mean1(float array[],int n)
{
int i;
float sum=0;
for(i=0;i<=n;i++)
sum=sum+array[i];
return (sum/n);
}
float median1(float array[],int n)
{
float temp;
int i,j;
for(i=n-1;i=>0;i--)
{
for(j=0;j<=i;j++)
{
if(array[j]>=array[j+1])
{
temp=array[j];
array[j]=array[j+1];
array[j+1]=temp;
}
}
}
if(n%2==0)
return (array[n/2]+array[n/2-1])/2;
else
return array[n/2];
}

float mode1(float array[],int n)
{
return (3*median1(array,n)-2*mean1(array,n));
}

double standarddeviation1(float array[],int n)
{
int j;
double max[100],sum,variance,mean;
mean=mean1(array,n);
sum=0;
for(j=0;j<=n;j++)
{
max[j]=pow((array[j]-mean),2);
sum+=max[j];
}
variance=sum/(j-1);
return sqrt(variance);
}




3 comments:

  1. WTF! mode = 3*median-2*mean ??

    ReplyDelete
  2. while compiling this program,i got an error ....In function ‘median1’:median.c:60:19: error: expected expression before ‘>’ token.How can it be solved??plz help...
    Thanks in advance....

    ReplyDelete