Difference between null pointer and NULL
What Exactly a null pointer? and pointer and NULL different or same?
Well Friends, According to the ISO C99 standard: An integer constant expression with value 0, or such an expression cast to type void *, is called null pointer constant. If a null pointer constant is converted to a pointer type, the resulting pointer is called a null pointer ( guaranteed to compare unequal to a pointer to any object or function).
Difference between null pointer and NULL
While null pointer is a pointer which is guaranteed not to point to any object , NULL is just a macro which defines null pointer.
Difference between null pointer and NULL
Labels:
Basics of C
C Program to print its own source code as an Output
main()
{
char *x = "main()
{
char *x = %c%s%c;
printf(x,34,x,34);
}";
printf(x,34,x,34);
}
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Labels:
Basics of C,
C Assignments
C Program without using main() Function
# include
# include
# define pop(u,v,w,x,y,z) w ## z ## v ## x
# define demofun pop(s,i,m,n,t,a)
int demofun()
{
printf("I run without Main...");
}
# include
# define pop(u,v,w,x,y,z) w ## z ## v ## x
# define demofun pop(s,i,m,n,t,a)
int demofun()
{
printf("I run without Main...");
}
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Labels:
Basics of C,
c,
C Assignments
code in c++ that defines a button class to draw a button
#include
#include
#include
#include
#include
#include
class button
{
private:
int x;
int y;
char *s;
public:
void draw()
{
if (textwidth(s)>50)
{
setfillstyle(SOLID_FILL, 7);
bar(x, y, x+textwidth(s)+4, y+20);
setcolor(15);
line(x, y, x+textwidth(s)+4, y);
line(x, y, x, y+20);
setcolor(8);
line(x+textwidth(s)+4, y, x+textwidth(s)+4, y+20);
line(x, y+20, x+textwidth(s)+4, y+20);
setcolor(0);
outtextxy(x+2, y+5, s);
return;
}
setfillstyle(SOLID_FILL, 7);
bar(x, y, x+45, y+20);
setcolor(15);
line(x, y, x+45, y);
line(x, y, x, y+20);
setcolor(8);
line(x+45, y, x+45, y+20);
line(x, y+20, x+45, y+20);
setcolor(0);
outtextxy(x+4, y+5, s);
};
void set(int a, int b, char *c)
{
x=a;
y=b;
strcpy(s, c);
};
};
int main(void)
{
int gdriver = DETECT, gmode, errorcode;
button c;
initgraph(&gdriver, &gmode, "");
c.set(100, 100, "Aymen");
c.draw();
delay(5000);
closegraph();
return 0;
}
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C++,
C++ Assignment
Pattern Matching in C
#include
#include
#include
void sgrep(char *filename, char *pattern);
int main(int argc, char *argv[])
{
char *filename;
FILE *file;
char *pattern;
int hit;
if(argc<2)
{
printf("missing argument\n");
}
else
{
if(argc==2)
{
filename = argv[1];
printf("Pattern to search for:\n");
scanf("%s",pattern);
sgrep(filename,pattern);
//printf("MAIN: hit=%d\n",hit);
}
}
return 0;
}
void sgrep(char *filename, char *pattern)
{
//Search file for the first character in the pattern
int i;
FILE *file;
char *chars = "1";
char *filedata;
char first;
int index;
int j;
int k;
int hit;
if((file=fopen(filename,"r"))==NULL)
{
printf("cannot open file %s\n",filename);
}
else
{
file=fopen(filename,"r");
char *data = (char*)malloc(100);
while(chars)
{
chars = fgets(data,100,file);
if(chars)
{
for(i=0;i
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C Assignments
HORNER rule to calculate value of a polynomial in C
int horner_rule(int poly[],int n,int x,int i){
if(i==n)
return poly[i];
else
return poly[i]+x*horner_rule(poly,n,x,i+1);
}
/*for equ like 2*x
*poly[]={0,2};
*/
int poly[]={1,2,3};// polynomial in the form 1+2*x+3*x*x....
int x0;
printf("enter value at which you want to calculate this polynomial :");
scanf("%d",&x0);
printf("%d",horner_rule(poly,(sizeof(poly))/sizeof(poly[0])-1,x0,0));
return 0;
}
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C Assignments
Creating C Program with Friend Functions and Function Overloading
#include
using namespace std;
int inputArraySetA[20];
int inputArraySetB[20];
//int inputArrayUnion[20];
int sizeSetA = 0;
int sizeSetB = 0;
//int sizeUnion = 0;
int temp = 0;
class Set
{
protected:
int x;
int y;
public:
Set();
Set(int px,int py);
void AddElement(int v);
void RemoveElement(int v);
void Print();
friend void Union(int inputArraySetA[20], int inputArraySetB[20]);
friend void Intersect(int inputArraySetA[20], int inputArraySetB[20]);
friend void Minus(int inputArraySetA[20], int inputArraySetB[20]);
};
//--------------------------------------------------------------------------------------------------------------------
void Union(int inputArraySetA[20], int inputArraySetB[20])
{
}
//--------------------------------------------------------------------------------------------------------------------
int main()
{
cout << "Enter First set of numbers, (-1) to quit: "<for (int i = 0; i < 20; i++)
{
cin >> temp;
if (temp == -1)
{
break;
}
else
{
inputArraySetA[i] = temp;
sizeSetA++;
}
}
cout << "Enter Second set of numbers, (-1) to quit: "<for (int i = 0; i < 20; i++)
{
cin >> temp;
if (temp == -1)
{
break;
}
else
{
inputArraySetB[i] = temp;
sizeSetB++;
}
}
cout << "Set A is ";
for (int i = 0; i < sizeSetA; i++)
{
cout << inputArraySetA[i] << " ";
}
cout << "\nSet B is ";
for (int i = 0; i < sizeSetB; i++)
{
cout << inputArraySetB[i] << " ";
}
return 0;
}
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C Assignments
Creating Isosceles Triangle in C
Creating Isosceles Triangle
#include
#define Mx 20
#define My 20
void draw(int base,int height);
int main()
{
// draw(5,4);
// draw(5,4);
// draw(15,6);
int a=2,h=0;
char c;
while(a%2==0){
printf("Enter the base:");
scanf("%d",&a);
if (a%2==0)
printf("only odd length is allowed\n");
getchar();
}
while (h==a || h<2){
printf("Enter the height :");
scanf("%d",&h);
if (h==a)
printf("\nthe height you entered makes an Equilateral triangle.\n");
if (h<2)
printf("\nheight must be greater than 1.\n");
getchar();
}
draw(a,h);
getchar();
}
void draw(int base,int height){
if(base%2==0) {
printf("The length of the base its not an odd number \n");
return ;
}
int i=0,j;
int a=i;
int b=base,t;
// (base>height)?t=base:t=height;
int howmanystars=(base)/(height-1);
float stars=height-1;
stars=(float)(base)/stars-0.5;
if (howmanystars<=stars)
howmanystars++;
int h=1;
for (i=0;i<=height;i++){
if (i==height-1)
h=base;
for (int k=0;k<=(base-h+1)/2;k++)
printf(" ");
for (j=0;j<=h;j++)
printf("*");
h=h+howmanystars;
printf("\n");
}
}
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Basics of C,
C Assignments
Cal volume of Cylinder using function in C
#include
#include
#define PI 3.142
int main () {
int radius;
int height;
int volume;
int program;
printf ("Enter 2 to start and 8 to quit\t");
scanf ("%d", &program);
while (program !=9)
{
printf ("Press \n 1 for radius \n 3 for height \n 5 to volume \n 9 to quit:\t");
scanf ("%d", &program);
if (program==1) {
printf ("Enter the value in radius\t");
scanf ("%d", &radius); }
if (program==3) {
printf ("Enter the value for height:\t");
scanf ("%d", &height); }
if (program==5) {
volume = PI * radius * radius * height;
printf ("\n VOLUME OF CYLINDER WITH RADIUS %dUNITS: & HEIGHT %dUNITS: IS %d CUBIC UNITS\n", radius, height, volume);
printf ("\n Do you wish to calculate the Volume of another Cylinder?\n"); }
}
system ("pause");
return 0;
}
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Points on Pointers
- A pointer containing garbage can not be detected in certain cases
- Abundance of operators are to be used carefully with pointers
- Passing pointers to double dimension arrays need other than first size to be specified
- Pointer to auto array of a function can not be passed back
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Relation between Pointers and Structures in C Language
Relation between Pointers and Structures in C :-
- struct inventory { char name[30];
- int number;
- float price; }
- product[2],*p;
- p = product; // assign zeroth element
- p -> name is same as (*p).name
- ++ptr->count increments count
- (++ptr)->count increments ptr and then return count
- ptr++->count is legal and increments ptr after accessing count
- *ptr->p fetches whatever p points to
- *ptr->p++ increments p after accessing whatever it points to
- (*ptr->p)++ increments whatever p points to
- *ptr++->p increments ptr after accessing whatever it points to
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Relation between Pointers and Functions in C
Relation between Pointers and Functions
- Passing a pointer to a function is known as call by reference and function works on actual variables in that case
- void copy(char *s1, char*s2) { while ((*s1++ = *s2++) != ‘\0’ }
- Pointer parameters are very common in string functions like above
- *s++ and *++s are different!
- type (*ptr)() is a pointer to a function with return type as type
- It is different than type *ptr()
- double (*p1)(), mul();
- p1 = mul;
- (*p1) (x,y) is same as mul(x,y)
- It is used in system programming
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Pointers and Char Strings
Pointers and Char Strings
- char name[20], *cptr = name; is valid
- while (*cptr != ‘\0’) or (*cptr) is true until the end of the string is reached
- while (*cptr); length = cptr – name;
- char *name; name = “Delhi” is accepted
- Char arrays with variable row length are called ragged arrays, better handled by ptrs
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Relationship between Pointers and Arrays in C
- Array name is a pointer to itself
- ANSI standard makes &a = a
- int x[10], *p = x; makes p = &x[0]
- while ( p < &x[4]) { sum+=*p; p++ }
- The compiler allocates contiguous space for all the elements row-wise in multidimensional arrays
- int x[10][20] and int *p = x is allowed
- When we increment i by 1, p will be incremented by the size of the row and not the size of the element itself
- p is pointer to first row, p+i is pointer to ith row, *(p+i) is the first element of the ith row
- *(p+i) + j is jth element of ith row
- *(*(p+i)+j) value stored in cell (i,j)
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Pointer Comparison in C
- p1 > p2 is true if p1 is having higher memory location than p2
- p1 == p2 and p1 !=p2 are also accepted as valid
- pointers to related variables like array or string elements makes sense
- Pointers can not be used in division, multiplication or addition
Related Links :
Labels:
Pointer types and Arrays
Pointer Expressions in C
- y = *p * *q // (*p) * (*q)
- sum += *p , *p2 = *p2 + 10
- z = 5 * - *p2/ *p1 //(5 * (-(*p2)))/(*p1)
- in above /* is not acceptable
- p+1, p – 4, p++, p- - are allowed
- p2 –p1 for the same array are no of elements in between them
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Accessing a Variable Through Pointer in C
- The indirection operator (*) is used to access the value of a variable by its ptr
- * can be remembered as value at address
- int n = *p // int *p = &quantity is done
- int n = *&quantity // is = quantity
- *5445 where 5445 is a valid location does not yield the content at that address
- *x=25 changes value of f indirectly
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Declaring and Initializing Pointers in C
- int *p; // p contains address of an int
- float *x // x contains address of a float
- p = &quantity // quantity is an int variable
- p = &f where f is float is an erroneous statement, because *p results in a wrong ans
- int x, *p = &x; // initializes p to address of x
- int *p=&x, x is invalid
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Pointer types and Arrays
Accessing The Address of a variable in Pointers in C
Accessing The Address of a variable
- The actual location of a variable in the memory is system dependent
- It may vary throughout the execution
- Address operator is used to access it
- &125, int x[10], &x, &(x+y) are illegal use of address operator
- &x[0] or &[x+i] are valid operations
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Address of a variable, Declaring and Initializing Pointers, Accessing a Variable Through Pointer, Pointer Expressions, Pointer Comparison.
So it will show you details of the : - Address of a variable, Declaring and Initializing Pointers, Accessing a Variable Through Pointer, Pointer Expressions, Pointer Comparison, Pointers and Arrays, Pointers and Char Strings, Pointers and Functions, Pointers and Structure.
Understanding Pointers
- Computer memory is a sequential collection of storage cells for data and instructions
- Each cell, has an address associated with it
- The addresses are numbered contiguously
- The last address depends on memory size
- During execution system always associates name of a variable with it’s address
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Program to perform some basic operations strcmp, strcat, strlen, strcpy on string in C Programming
This program shows Program to perform some basic operations of inbuilt function like strcmp, strcat, strlen, strcpy on string in C Programming.
#include
#include
#include
int xstrlen ( char * ) ;
void xstrcpy ( char *, char * ) ;
void xstrcat ( char *, char * ) ;
int xstrcmp ( char *, char * ) ;
void show ( char * ) ;
void main( )
{
char s1[ ] = "kicit" ;
char s2[ ] = "Nagpur" ;
char s3[20] ;
int len ;
clrscr( ) ;
printf ( "\nString s1: %s", s1 ) ;
len = xstrlen ( s1 ) ;
printf ( "\nlength of the string s1: %d", len ) ;
printf ( "\nString s2: %s", s2 ) ;
xstrcpy ( s3, s1 ) ;
printf ( "\nString s3 after copying s1 to it: %s", s3 ) ;
xstrcat ( s3, s2 ) ;
printf ( "\nString s3 after concatenation: %s", s3 ) ;
if ( xstrcmp ( s1, s2 ) == 0 )
printf ( "\nThe strings s1 and s2 are similar" ) ;
else
printf ( "\nThe strings s1 and s2 are not similar" ) ;
getch( ) ;
}
/* finds the length of the string */
int xstrlen ( char *s )
{
int l = 0 ;
while ( *s )
{
l++ ;
s++ ;
}
return l ;
}
/* copies source string s to the target string t */
void xstrcpy ( char *t, char *s )
{
while ( *s )
{
*t = *s ;
t++ ;
s++ ;
}
*t = '\0' ;
}
/* concatenates the two strings */
void xstrcat ( char *t, char *s )
{
while ( *t )
t++ ;
while ( *s )
*t++ = *s++ ;
*t = '\0' ;
}
/* compares two strings s and t for equality */
int xstrcmp ( char *s, char *t )
{
while ( *s == *t )
{
if ( ! ( *s ) )
return 0 ;
s++ ;
t++ ;
}
return ( *s - *t ) ;
}
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C Assignments
Simple program to assign values to many variables in one line in C language
Simple program to assign values to many variables in one line in C language, in one line multiple values in c .
#include
main()
{
int i,j,k;
k = (i = 4, j = 5);
printf("k = %d",k);
}
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Labels:
Basics of C,
C Assignments
Program to Show example of the 2D array of int using pointers.in cpp
Program to Show example of the 2D array of int using pointers in C++ Language, two dimensional array with pointers.
#include
#include
main( )
{
clrscr();
constint r=3;
constint c=3;
int array[r][c],i,j;
cout<<"\n Enter the contents of the 2D array row by row are :\n"<<endl;
for(i=0;i<r;i++)
{
for(j=0;j<c;j++)
cin>>*(*(array+i)+j);
cout<
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Labels:
C++ Assignment
Program to illustrate the functions returning pointers in c++
#include
#include
int *function();
main()
{
clrscr();
int *p;
p=function();
cout<<"\n Value return by the function returning pointer :"<<<"\t value of *p = "<<*p<
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C++ Assignment
Functions with arguments but no return values in C
C Program to show Functions with arguments but no return values example Code is given below :
Output
Enter principal amount, interest rate, and period
5000 0.12 5
ZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ
5000.000000 0.120000 5 8811.708984
CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC
/* prototypes */
void printline (char c);
voidvalue (float, float, int);
main( )
{
float principal, inrate;
int period;
printf("Enter principal amount, interest");
printf(" rate, and period \n");
scanf("%f %f %d",&principal, &inrate, &period);
printline('Z');
value(principal,inrate,period);
printline('C');
}
void printline(char ch)
{
int i ;
for(i=1; i <= 52; i++)
printf("%c",ch);
printf("\n");
}
voidvalue(float p, float r, int n)
{
int year ;
float sum ;
sum = p ;
year = 1;
while(year <= n)
{
sum = sum * (1+r);
year = year +1;
}
printf("%f\t%f\t%d\t%f\n",p,r,n,sum);
}
Output
Enter principal amount, interest rate, and period
5000 0.12 5
ZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ
5000.000000 0.120000 5 8811.708984
CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC
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Labels:
Basics of C,
C Assignments
Use of break statement in a program in C Language
main()
{
int m;
float x, sum, average;
printf("This program computes the average of a
set of numbers\n");
printf("Enter values one after another\n");
printf("Enter a NEGATIVE number at the end.\n\n");
sum = 0;
for (m = 1 ; m < = 1000 ; ++m)
{
scanf("%f", &x);
if (x < 0)
break;
sum += x ;
}
average = sum/(float)(m-1);
printf("\n");
printf("Number of values = %d\n", m-1);
printf("Sum = %f\n", sum);
printf("Average = %f\n", average);
}
Output
This program computes the average of a set of numbers
Enter values one after another
Enter a NEGATIVE number at the end.
21 23 24 22 26 22 -1
Number of values = 6
Sum = 138.000000
Average = 23.000000
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C Assignments
Program to display series 2,4,16,256... using while loop in C
#include
#include
int main()
{
int n,x; // declare the variable longdouble i=2; //declare the variable of long double type
clrscr();
printf("Enter the number : ");
scanf("%d",&n);
printf("\n");
x=1;
while(x<=n) // loop will be execute till the value of x I less or equal n
{
printf("%.2Lf\n",i); // print the value of I upto 2 decimals only
x++;
i*=i;
}
getch();
return 0;
}
Output:
Enter the number : 4
2.00
4.00
16.00
256.00
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Labels:
C Assignments
Program to check whether a number is a member of given list or not in Artificial Intelligence In C
domains
list=integer*
predicates
findnum(integer,list)
clauses
findnum(X,[]):-
write("\nNumber Is Not Found").
findnum(X,[X|Tail]):-
write("\nNumber Is Found").
findnum(X,[Y|Tail]):-
findnum(X,Tail).
OUT PUT
=======
Goal: findnum(3,[1,2,3,4,5])
Number Is Found
Yes
----------------------------
Goal: findnum(6,[1,2,3,4,5])
Number Is Not Found
Yes
----------------------------
Goal: findnum(2,[1,2,2,1])
Number Is Found
Yes
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Labels:
C Assignments
PROGRAM THAT CHECK WHETHER THE GIVEN NUMBER IS PRIME IN PARALLEL in C Programming
#include "forkjoin.h"
#include "shared.h"
main()
{
int a[10],n;
int *flag,fect=1,nproc;
int i,pid,shmid;
printf("Enter the value of the no. n : ");
scanf("%d",&n);
printf("Enter the no. of process : ");
scanf("%d",&nproc);
flag=(int *) create_memory(sizeof(int)*nproc,&shmid);
for(i=0;i<=nproc;i++)
flag[i]=0;
pid=create_process(nproc);
for(i=pid+2;i<=n;i+=nproc)
{
if(n%i==0)
flag[pid]=1;
}
join_process(nproc,pid);
for(i=0;i<=nproc;i++)
{
if(flag[i]==1)
{
printf("Given no. is not prime\n");
exit(1);
}
}
printf("Given no. is prime\n",fect);
clear_memory(&shmid);
}
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C Assignments
Size and Range of Basic Data Types in C Language
Size and Range of Basic Data Types
Data Type | Range of Values |
char or signed char | -128 to 127 |
unsigned char | 0 to 255 |
int or signed int | -32768 to 32767 |
unsigned int | 0 to 65536 |
long int | -2,147483,648 to + ..47 |
float | 3.4e-38 to 3.4e+38 |
double | 1.7e-308 to 1.7e+308 |
Floating Point Types
- They are stored in 32 bits in all 16 or 32 bit machines with 6 digits of precision
- Double provides more accuracy than float
- It uses 64 bits giving a precision of 14 digits
- It represents the same data type as float but with double precision, hence double
- To extend the precision further, one may use long double with 80 bits
Related Links :
Labels:
Basics of C,
c
Program of BISECTION METHOD in C Language
#include
#include
#include
#define ESP 0.001
#define F(x) (x)*(x)*(x) + (x)*(x) + (x) + 7
void main()
{
int i = 1;
float x0,x1,x2;
double f1,f2,f0,t;
clrscr();
printf("\nEnter the value of x0: ");
scanf("%f",&x0);
printf("\nEnter the value of x1: ");
scanf("%f",&x1);
printf("\n__________________________________________________________________\n");
printf("\niteration\t x0\t x1\t x2\t f0\t f1\t f2");
printf("\n___________________________________________________________________\n");
do
{
x2=(x0+x1)/2;
f0=F(x0);
f1=F(x1);
f2=F(x2);
printf("\n%d %f %f %f %lf %lf %lf", i, x0,x1,x2,f0,f1,f2);
if(f0*f2<0)
{
x1=x2;
}
else
{
x0=x2;
}
i++;
}while(fabs(f2)>ESP);
printf("\n__________________________________________________________\n");
printf("\n\nApp.root = %f",x2);
getch();
}
OUTPUT :
Enter the value of x0: -2
Enter the value of x0: -1
Enter the value of x1: -2
__________________________________________________________
x0 x1 x2 f0 f1 f2
__________________________________________________________
-1.000000 -2.000000 -1.500000 -5.000000 2.000000 -1.750000
-1.500000 -2.000000 -1.750000 -1.750000 2.000000 0.062500
-1.500000 -1.750000 -1.625000 -1.750000 0.062500 -0.859375
-1.625000 -1.750000 -1.687500 -0.859375 0.062500 -0.402344
-1.687500 -1.750000 -1.718750 -0.402344 0.062500 -0.170898
-1.718750 -1.750000 -1.734375 -0.170898 0.062500 -0.054443
-1.734375 -1.750000 -1.742188 -0.054443 0.062500 0.003967
-1.734375 -1.742188 -1.738281 -0.054443 0.003967 -0.025253
-1.738281 -1.742188 -1.740234 -0.025253 0.003967 -0.010647
-1.740234 -1.742188 -1.741211 -0.010647 0.003967 -0.003341
-1.741211 -1.742188 -1.741699 -0.003341 0.003967 0.000313
__________________________________________________________
App.root = -1.741699
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Labels:
C Assignments
C Language Program to evaluate fibonacci series and checking whether or not it is fibonacci number
#include
#include
void main()
{
longint a=0,b=1,i,sum,n,j=0,m;
clrscr();
printf(" Please Enter value for N: ");
scanf("%ld",&n);
printf("\n PLEASE ENTER THE CHECKING NO.: ");
scanf("%ld",&m);
printf("\n\n\t\t\t IT IS FEBONACCI SERIES \n ");
printf("%ld ,",a);
printf("%ld ,",b);
for(i=2;i<=n;i++)
{
sum = a+b;
a = b;
b = sum;
if(sum==m)
j=1;
printf("%ld ,",sum);
}
if(j==1)
printf("\n\n\t\t\t %ld IT IS FEBONNACI NUMBER. ",m);
else
printf("\n\n\t\t\t %ld IT IS NOT FEBONNACI NUMBER. ",m);
getch();
}
Output :
Please Enter valuefor N: 9
PLEASE ENTER THE CHECKING NO.: 21
IT IS FEBONACCI SERIES
0 ,1 ,1 ,2 ,3 ,5 ,8 ,13 ,21
21 IT IS FEBONNACI NUMBER.
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program to print the factorial of first five elements of the fibonacci series
# include
# include
long fibonacci(long);
long factorial(long);
int main( )
{
clrscr( );
cout<<"\n The first five elements of the fibonacci series are : ";
for(int count_1=0;count_1<5;count_1++)
cout<
cout<<"\n\n The factorial first five elements of the fibonacci series are : ";
for(int count_2=0;count_2<5;count_2++)
cout<
getch( );
return 0;
}
/*************************************************************************//*************************************************************************///------------------------ Function Definitions -----------------------///*************************************************************************//*************************************************************************//*************************************************************************///-------------------------- fibonacci(long) --------------------------///*************************************************************************/long fibonacci(long number)
{
if(number==0 || number==1)
return number;
elsereturn fibonacci(number-1)+fibonacci(number-2);
}
/*************************************************************************///-------------------------- factorial(long) --------------------------///*************************************************************************/long factorial(long number)
{
int count=1;
int factorial=1;
if(number==0)
factorial=1;
else
{
do
{
factorial=factorial*count;
count++;
}
while(count<=number);
}
return factorial;
}
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Program to display dimond shape triangle in C Programming
#include
#include
void main(){
int i,j,k,m,num,c;
clrscr();
printf("*****Logical Square*****\n");
printf("Enter number of lines u want : ");
scanf("%d",&num);
printf("\n\n");
//for top partfor(i=1;i<=num;i++)
{
c=num;
for(j=1;j<=(num-i)+2;j++)
putchar(' ');
for(k=1;k<=i;k++)
printf("%d",c--);
c++;
for(m=c;m<=num;m++)
{
printf("%d",++c);
}
printf("\n");
}
//for bottom partfor(i=1;i<=num;i++)
{
c=num;
for(j=num;j>=(num-i);j--)
putchar(' ');
for(k=c;k>i;k--)
printf("%d",k);
for(m=k;m<=c;m++)
printf("%d",m);
printf("\n");
}
getch();
}
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Program to display numeric triangle for user given value in C++ Programming Language
#include
#include
void main()
{
int i,num,j;
clrscr();
cout<<"Enter number for corresponding output:- ";
cin>>num;
for(i=1;i<=num;i++)
{
for(j=1;j<=i;j++)
{
cout< }
cout<<"\n";
}
num--;
getch();
}
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Program to display inputted string in ascending triangle and descending triangle in C
#include
#include
void main(){
char str[]="C Programming For You..";
int i,choice;
while(1){
clrscr();
printf("*****C Programming For You*****\n\n");
printf("1) Ascending style\n");
printf("2) Decending style\n");
printf("3) Exit\n");
printf("Enter your choice : ");
scanf("%d",&choice);
printf("\n\n");
switch(choice){
case 1: //Ascending Stylefor(i=0;str[i]!='\0';i++)
printf("%.*s\n",i,str);
printf("%.*s\n",i,str);
getch();
break;
case 2: //Decending Stylefor(i=0;str[i]!='\0';i++);
while(i>0){
printf("%.*s\n",i,str);
i--;
}
getch();
break;
case 3: exit(1);
default : printf("\n\nInvalid choice\n\n");
getch();
}
}
}
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PROGRAM USNG WHILE LOOP FOR THE FIBONANSI SERIES AS SHOWN IN DESCRIPTION in C Programming
#include
#include
#include
void main()
{
int n,i,j;
clrscr();
printf("Enter the No :- ");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
printf("\n");
for(j=1;j<=i;j++)
{
printf("%3d",i);
}
}
getch();
}
********
OUTPUT
********
Enter the No :- 7
1
2 2
3 3 3
4 4 4 4
5 5 5 5 5
6 6 6 6 6 6
7 7 7 7 7 7 7
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PROGRAM USNG WHILE LOOP FOR THE FIBONANSI SERIES IN TRIANGLE SERIES in C Language
#include
#include
#include
void main()
{
int n,i,j,m,k;
clrscr();
printf("Enter the No :- ");
scanf("%d",&n);
m=n;
for(i=1;i<=n;i++)
{
printf("\n\t");
for(k=1;k<=m;k++)
{
printf(" ");
}
for(j=1;j<=i;j++)
{
printf("%2d",i);
}
m--;
}
getch();
}
********
OUTPUT
********
Enter the No :- 6
1
2 2
3 3 3
4 4 4 4
5 5 5 5 5
6 6 6 6 6 6
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Program to solve the Towers of Hanoi Problem (using Recursive Algorithm) in C++ Programming
# include
# include
void move(constint n,constint fromTower,constint toTower,constint spareTower)
{
if(n>0)
{
move((n-1),fromTower,spareTower,toTower);
cout<<"\t Move the Top Disk from Tower-"<<<" to Tower-"< <<"\n";
move((n-1),spareTower,toTower,fromTower);
}
}
int main( )
{
clrscr( );
cout<<"\n\t ************** TOWERS OF HANOI **************\n"<<<"\t The Mystery of Towers of Hanoi is as follows : \n"< <<"\n\t *************************************************";
getch( );
return 0;
}
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program to show Recursive Function operations of fibonacci series in C Programming
#include
#include
#include
void fibo(int *);
void fact(int *);
void rev(char *);
void main()
{
void input(void);
clrscr();
input();
// fibo(n);
getch();
}
void input(void)
{
FILE *fp;
int i,*no,ctr;
char * str,choice;
fp=fopen("input1.txt","w");
ctr=0;
while(1)
{
printf("\n DO YOU WANT TO ENTER AGAIN::");
fflush(stdin);
scanf("%c",&choice);
if(choice=='y')
{
printf("\n ENTER THE NO FOR FIBONACCII AND FACTORIAL::");
scanf("%d",no);
printf("\n ENTER THE STRING FOR REVESE::");
scanf("%s",str);
fprintf(fp,"%d %s\n",*no,str);
ctr++;
}
elsebreak;
}
fclose(fp);
fp=fopen("input1.txt","r");
for(i=1;i<=ctr;i++)
{
fscanf(fp,"%d %s",no,str);
fibo(no);
fact(no);
rev(str); // printf("\nfrom file %d %s",*no,str);
}
fclose(fp);
}
void fibo(int * n)
{
FILE * fout;
int fibonaccii(int*,int*,int*,int *,FILE *);
int fno1=0,sno1=1,*fno,*sno,*tno;
fno=&fno1;
sno=&sno1;
fout=fopen("output1.txt","a");
fprintf(fout,"\n FIBONACII SERICE OF %d",*n);
fprintf(fout,"\n%d\t%d",*fno,*sno);
fibonaccii(fno,sno,tno,n,fout);
fclose(fout);
}
int fibonaccii(int *fno,int *sno,int *tno,int * n,FILE * fout)
{
*tno=*fno+*sno;
*fno=*sno;
*sno=*tno;
if(*tno>*n)
return(0);
else
{
fprintf(fout,"\t%d",*tno);
fibonaccii(fno,sno,tno,n,fout);
}
return(0);
}
void fact(int * no1)
{
FILE * fout;
int factorial(int *,int,int *,FILE *);
int ctr1=1,*ctr,no;
ctr=&ctr1;
fout=fopen("output1.txt","a");
fprintf(fout,"\n FACTORIAL OF %d",*no1);
fprintf(fout,"\n%d",*ctr);
ctr1++;
ctr=&ctr1;
no=*no1;
factorial(no1,no,ctr,fout);
// fprintf(fout,"\n%d",*no1);
fclose(fout);
}
int factorial(int * no1,int no,int * ctr,FILE * fout)
{
if(no%*ctr==0)
{
fprintf(fout,"\t%d",*ctr);
no=no / *ctr;
factorial(no1,no,ctr,fout);
}
else
{
*ctr=*ctr+1;
if(no<=1)
{
fprintf(fout,"\t%d",*no1);
return(0);
}
factorial(no1,no,ctr,fout);
}
}
void rev(char * str)
{
FILE * fout;
int *ctr;
int reverse1(int * ,char *,FILE *);
fout=fopen("output1.txt","a");
fprintf(fout,"\n REVERSE OF %s IS::",str);
*ctr=strlen(str);
reverse1(ctr,str,fout);
fclose(fout);
}
int reverse1(int * ctr,char * str,FILE * fout)
{
char * rev=str+*ctr-1;
if(*ctr!=0)
{
fprintf(fout,"%c",*rev);
*ctr=*ctr-1;
reverse1(ctr,str,fout);
}
elsereturn(0);
}
**************************INPUT*************************************
5 jolly
**************************OUTPUT*************************************
FIBONACII SERICE OF 5
0 1 1 2 3 5
FACTORIAL OF 5
1 5
REVERSE OF jolly IS::ylloj
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Program that implements circular queue as an array in C Language
#include
#include
#define MAX 10
void addq ( int *, int, int *, int * ) ;
int delq ( int *, int *, int * ) ;
void display ( int * ) ;
void main( )
{
int arr[MAX] ;
int i, front, rear ;
clrscr( ) ;
/* initialise data member */
front = rear = -1 ;
for ( i = 0 ; i < MAX ; i++ )
arr[i] = 0 ;
addq ( arr, 14, &front, &rear ) ;
addq ( arr, 22, &front, &rear ) ;
addq ( arr, 13, &front, &rear ) ;
addq ( arr, -6, &front, &rear ) ;
addq ( arr, 25, &front, &rear ) ;
printf ( "\nElements in the circular queue: " ) ;
display ( arr ) ;
i = delq ( arr, &front, &rear ) ;
printf ( "Item deleted: %d", i ) ;
i = delq ( arr, &front, &rear ) ;
printf ( "\nItem deleted: %d", i ) ;
printf ( "\nElements in the circular queue after deletion: " ) ;
display ( arr ) ;
addq ( arr, 21, &front, &rear ) ;
addq ( arr, 17, &front, &rear ) ;
addq ( arr, 18, &front, &rear ) ;
addq ( arr, 9, &front, &rear ) ;
addq ( arr, 20, &front, &rear ) ;
printf ( "Elements in the circular queue after addition: " ) ;
display ( arr ) ;
addq ( arr, 32, &front, &rear ) ;
printf ( "Elements in the circular queue after addition: " ) ;
display ( arr ) ;
getch( ) ;
}
/* adds an element to the queue */
void addq ( int *arr, int item, int *pfront, int *prear )
{
if ( ( *prear == MAX - 1 && *pfront == 0 ) || ( *prear + 1 == *pfront ) )
{
printf ( "\nQueue is full." ) ;
return ;
}
if ( *prear == MAX - 1 )
*prear = 0 ;
else
( *prear )++ ;
arr[*prear] = item ;
if ( *pfront == -1 )
*pfront = 0 ;
}
/* removes an element from the queue */
int delq ( int *arr, int *pfront, int *prear )
{
int data ;
if ( *pfront == -1 )
{
printf ( "\nQueue is empty." ) ;
return NULL ;
}
data = arr[*pfront] ;
arr[*pfront] = 0 ;
if ( *pfront == *prear )
{
*pfront = -1 ;
*prear = -1 ;
}
else
{
if ( *pfront == MAX - 1 )
*pfront = 0 ;
else
( *pfront )++ ;
}
return data ;
}
/* displays element in a queue */
void display ( int * arr )
{
int i ;
printf ( "\n" ) ;
for ( i = 0 ; i < MAX ; i++ )
printf ( "%d\t", arr[i] ) ;
printf ( "\n" ) ;
}
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Program that performs add, edit, delete, display and search date from file in C
#include
#include
struct biodata
{
int recno,age;
char name[20],sex;
float salary;
};
void main(){
void addData(void);
void delData(void);
void showAll(void);
void showRecord(void);
void alterData(void);
char choice;
clrscr();
while(1)
{
clrscr();
textcolor(BLACK);
cprintf(" R E S U M E \r\n");
printf("\n\n*****ENTER YOUR CHOICE*****\n");
printf("1) ADD DATA\n");
printf("2) DELETE DATA\n");
printf("3) SHOW ALL\n");
printf("4) SHOW RECORD\n");
printf("5) ALTER DATA\n");
printf("6) Exit \n");
printf("Enter your choice : ");
fflush(stdin);
choice = getche();
switch(choice){
case'1' : //call add data
addData();
break;
case'2' : //call delete databreak;
case'3' : //call show all data
showAll();
break;
case'4' : //call show record
showRecord();
break;
case'5' : //call alter databreak;
case'6' :
case 27 : clrscr();
gotoxy(25,10);
_setcursortype(_NOCURSOR);
textcolor(LIGHTMAGENTA);
cprintf("THANKS FOR USING THIS SOFTWARE");
getch();
exit(1);
}
}
}
//Adding Record to Filevoid addData(){
FILE *fp;
struct biodata obj;
fp = fopen("biodata.txt","a+t");
clrscr();
printf("\n*****ADDING DATA*****\n");
printf("\nEnter Record No : ");
scanf("%d",&obj.recno);
printf("Enter Name : ");
fflush(stdin);
scanf("%s",obj.name);
printf("Enter age : ");
scanf("%d",&obj.age);
fflush(stdin);
printf("Enter Sex : ");
scanf("%c",&obj.sex);
printf("Enter Salary : ");
scanf("%f",&obj.salary);
fscanf(stdin,"%d %s %d %c %f",&obj.recno,obj.name,&obj.age,&obj.sex,&obj.salary);
fprintf(fp,"%d %s %d %c %f",obj.recno,obj.name,obj.age,obj.sex,obj.salary);
fclose(fp);
}
void showRecord(){
FILE *fp;
struct biodata obj;
int rec;
long pos;
fp = fopen("biodata.txt","r");
clrscr();
printf("\n*****SHOWING SPECIFIC RECORD*****\n");
printf("\nEnter Record No : ");
scanf("%d",&rec);
pos = rec * sizeof(obj);
fseek(fp,pos,SEEK_SET);
if(feof(fp)==0)
printf("\n\nNO DATA FOUND\n");
else{
fscanf(fp,"%d %s %d %c %f",&obj.recno,obj.name,&obj.age,&obj.sex,&obj.salary);
printf("\n\n\tRecord No : %d\n",obj.recno);
printf("\tName : %s\n",obj.name);
printf("\tAge : %d\n",obj.age);
printf("\tSex : %c\n",obj.sex);
printf("\tSalary : %f\n",obj.salary);
}
getch();
fclose(fp);
}
void showAll()
{
FILE *fp;
struct biodata obj;
int totrec,i;
fp = fopen("biodata.txt","r");
clrscr();
fseek(fp,0,SEEK_END);
totrec=ftell(fp)/sizeof(obj);
printf("\n*****SHOWING ALL RECORD*****\n");
printf("\n\nRecord_No\tName\t\tAge\tSex\tSalary\n\n");
printf("\n\n%d\n",totrec);
for(i=1;i<=totrec;i++){
fscanf(fp,"%d %s %d %c %f",&obj.recno,obj.name,&obj.age,&obj.sex,&obj.salary);
fprintf(stdout,"%-15d %-15s %-8d %-2c %10.2f\n",obj.recno,obj.name,obj.age,obj.sex,obj.salary);
}
getch();
fclose(fp);
}
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Program to copy the contents of one array to another Without Shared Memory in C Language
# include
# include "forkjoin.h"int main()
{
int arr1[10]={1,1,1,1,1,1,1,1,1,1};
int arr2[10]={2,2,2,2,2,2,2,2,2,2};
int id;
int iCount;
/* Copy Array-1 to Array-2 Using 2 Processes */
id=process_fork(2);
if(id==0)
{
/* Parent Process */
for(iCount=0;iCount<10;iCount=iCount+2)
{
arr2[iCount]=arr1[iCount];
}
}
else
{
/* Child Process */for(iCount=1;iCount<10;iCount=iCount+2)
{
arr2[iCount]=arr1[iCount];
}
}
process_join(2,id);
/* Here Child Process is Completed and We have not made Array 2 Shared So Changes made by Child Process is not visible in Parent Process */
printf("\n Array 2 ... \n");
for(iCount=0;iCount<10;iCount++)
{
printf("arr2[%d] : %d\n",iCount,arr2[iCount]);
}
return 0;
}
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Program to create histogram using threading in C language
#include
#include
#include
int a[100], size, N;
int min, max;
int grno;
float grsize;
int histo[50];
int start=0;
pthread_mutex_t lock;
pthread_cond_t cond;
void * work()
{
int i, temp;
pthread_mutex_lock(&lock);
if(start==0)
pthread_cond_wait(&cond, &lock);
pthread_mutex_unlock(&lock);
for(;;)
{
pthread_mutex_lock(&lock);
i=size-1;
size--;
pthread_mutex_unlock(&lock);
if(size<0) { pthread_mutex_lock(&lock); pthread_cond_wait(&cond, &lock); pthread_mutex_unlock(&lock); } if(i<0) break; if(min>a[i])
min=a[i];
if(max<0) break; temp=(float)((a[i]-min))/grsize; if(temp >(grno-1))
temp= grno-1;
histo[temp]++;
}
}
int main()
{
pthread_t id;
void * status;
int i, nthread;
int temp1, temp2;
pthread_mutex_init(&lock,0);
pthread_cond_init(&cond,0);
printf("Enter the size of the array :: ");
scanf("%d",&size);
N=size;
printf("\nEnter the %d elements of array\n",N);
for(i=0;i=0)
sleep(1);
grsize=(float)(max-min)/(float)grno;
size=N;
pthread_mutex_lock(&lock);
pthread_cond_broadcast(&cond);
pthread_mutex_unlock(&lock);
while(size>=0)
sleep(1);
pthread_join(id,status);
printf("\nThe histogram is as follows::\n");
temp1=min;
temp2=ceil(grsize);
for(i=0;i%d = %d\n",temp1, temp2,histo[i]);
temp1=temp2+1;
temp2+=ceil(grsize);
}
else
printf("For %d and up values = %d ",temp1, histo[i]);
}
pthread_mutex_destroy(&lock);
printf("\n");
return 0;
}
OUTPUT:
--------
Enter the size of the array :: 4
Enter the 4 elements of array
1
2
3
4
Enter the total number of groups required in histogram :: 4
Enter the total number of threads :: 3
The histogram isas follows::
For 1 -> 1 = 1
For 2 -> 2 = 1
For 3 -> 3 = 1
For 4 and up values = 1
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c,
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Program to show two-dimensional arrays in C Programming
#define MAXGIRLS 4
#define MAXITEMS 3
main()
{
intvalue[MAXGIRLS][MAXITEMS];
int girl_total[MAXGIRLS] , item_total[MAXITEMS];
int i, j, grand_total;
/*.......READING OF VALUES AND COMPUTING girl_total ...*/
printf("Input data\n");
printf("Enter values, one at a time, row-wise\n\n");
for( i = 0 ; i < MAXGIRLS ; i++ ) { girl_total[i] = 0; for( j = 0 ; j < MAXITEMS ; j++ ) { scanf("%d", &value[i][j]); girl_total[i] = girl_total[i] + value[i][j]; } } /*.......COMPUTING item_total..........................*/ for( j = 0 ; j < MAXITEMS ; j++ ) { item_total[j] = 0; for( i =0 ; i < MAXGIRLS ; i++ ) item_total[j] = item_total[j] + value[i][j]; } /*.......COMPUTING grand_total.........................*/ grand_total = 0; for( i =0 ; i < MAXGIRLS ; i++ ) grand_total = grand_total + girl_total[i]; /* .......PRINTING OF RESULTS...........................*/ printf("\n GIRLS TOTALS\n\n"); for( i = 0 ; i < MAXGIRLS ; i++ ) printf("Salesgirl[%d] = %d\n", i+1, girl_total[i] ); printf("\n ITEM TOTALS\n\n"); for( j = 0 ; j < MAXITEMS ; j++ ) printf("Item[%d] = %d\n", j+1 , item_total[j] ); printf("\nGrand Total = %d\n", grand_total); }
Output :
Input data
Enter values, one at a time, row_wise
310 257 365
210 190 325
405 235 240
260 300 380
GIRLS TOTALS
Salesgirl[1] = 950
Salesgirl[2] = 725
Salesgirl[3] = 880
Salesgirl[4] = 940
ITEM TOTALS
Item[1] = 1185
Item[2] = 1000
Item[3] = 1310
Grand Total = 3495
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Basics of C,
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Program that prints triangle of numbers in reverse pattern in C Programming
#include
#include
void main()
{
int i,n,j;
clrscr();
printf("\n Please Give The Value of N: ");
scanf("%d",&n);
for(i=n;i>=1;i--)
{
for(j=i;j>=1;j--)
printf("%d ",j);
printf("\n");
}
getch();
}
****************************** OUTPUT *********************************
Please Give The Value of N: 5
5 4 3 2 1
4 3 2 1
3 2 1
2 1
1
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Program to print triangle of numbers in reverse pattern in C Programming
#include
#include
void main()
{
int i,n,j;
clrscr();
printf("\n Please Give The Value of Number of *: ");
scanf("%d",&n);
for(i=n;i>=1;i--)
{
for(j=1;j<=i;j++)
printf("%d ",j);
printf("\n");
}
getch();
}
****************************** OUTPUT *********************************
Please Give The Value of N: 7
1 2 3 4 5 6 7
1 2 3 4 5 6
1 2 3 4 5
1 2 3 4
1 2 3
1 2
1
***********************************************************************
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C Project to create a Notepad Editor Utility With Menu Bar In C
#include
#include
#include
#include
#include
#include
char far *vid=0xB8000000;
char a[50000],*str;
int track[2000],fp=1,lp=21,cl=1,p=0,t=0,eat;
/*This function writes a character into video memory.*/
writechar(char ch,int attr,int row,int col)
{
char far *v;
v=vid+row*160+col*2;
*v=ch;
v++;
*v=attr;
}/*End wrotechar*/
//-----------------------------------------------------------------------
/*This function draws a box of given attribute & size*/
drawbox(int r1,int c1,int r2,int c2,int attr)
{ int i,j;
for(i=r1;i<=r2;i++)
{ for(j=c1;j<=c2;j++)
writechar(' ',attr,i,j);
}
}/*End drawbox*/
//------------------------------------------------------------------------
/*This function draws the screen at starting*/
drawscreen()
{ drawbox(0,0,0,79,120);
drawbox(24,0,24,79,120);
drawbox(1,0,23,79,16);
doubleborder(1,0,23,79,31);
}/*End drawscreen*/
//------------------------------------------------------------------------
/*This function refreshes the screen*/
refreshscreen()
{ int r,c;
drawbox(2,1,22,78,16);
}/*End Refreshscreen*/
//-------------------------------------------------------------------------
/*This function draws the double border*/
doubleborder(int r1,int c1,int r2,int c2,int attr)
{ int r,c;
writechar(201,attr,r1,c1);
writechar(187,attr,r1,c2);
writechar(200,attr,r2,c1);
writechar(188,attr,r2,c2);
for(c=(c1+1);c<=(c2-1);c++)
writechar(205,attr,r1,c);
for(c=(c1+1);c<=(c2-1);c++)
writechar(205,attr,r2,c);
for(r=(r1+1);r<=(r2-1);r++)
writechar(186,attr,r,c1);
for(r=(r1+1);r<=(r2-1);r++)
writechar(186,attr,r,c2);
}/*End doubleborder*/
//---------------------------------------------------------------------------
/*This function draws border of given attribute & size*/
drawborder(int r1,int c1,int r2,int c2,int attr)
{ int r,c;
writechar(218,attr,r1,c1);
writechar(191,attr,r1,c2);
writechar(192,attr,r2,c1);
writechar(217,attr,r2,c2);
r=r1;
for(c=c1+1;c<=c2-1;c++)
writechar(196,attr,r,c);
r=r2;
for(c=c1+1;c<=c2-1;c++)
writechar(196,attr,r,c);
c=c1;
for(r=r1+1;r<=r2-1;r++)
writechar(179,attr,r,c);
c=c2;
for(r=r1+1;r<=r2-1;r++)
writechar(179,attr,r,c);
}/*End drawborder*/
//---------------------------------------------------------------------------
/*This function draws a line of given attribute*/
drawline(int r,int c1,int c2,int attr)
{ int i;
writechar(195,attr,r,c1);
writechar(180,attr,r,c2);
for(i=c1+1;i<=c2-1;i++)
writechar(196,attr,r,i);
}/*End drawline*/
//---------------------------------------------------------------------------
/*This function writes a string in given row & column with given attribute*/
writestring(char *p,int attr,int r,int c)
{ int l,i;
l=strlen(p);
for(i=0;i<=l;i++)
{ writechar(*(p+i),attr,r,c);
c++;
}
}/*End writestring*/
//---------------------------------------------------------------------------
/*This function saves the content of videomemory from r1,c1 to r2,c2
into main memory using char buffer*/
char *savemem(int r1,int c1,int r2,int c2,char *buff)
{ char far *v;
int i,j,k=0,size;
size=(r2-r1+1)*(c2-c1+1)*2;
buff=(char *)malloc(size);
for(i=r1;i<=r2;i++)
{ for(j=c1;j<=c2;j++)
{ v=(vid+i*160+j*2);
*(buff+k)=*v;
k++;
v++;
*(buff+k)=*v;
k++;
}
}
return(buff);
}/*End savememo*/
//---------------------------------------------------------------------------
/*This function restores the content of main memory into videomemory
from r1,c1 to r2,c2 using char buffer*/
restoremem(int r1,int c1,int r2,int c2,char *buff)
{ char far *v;
int i,j,k=0;
for(i=r1;i<=r2;i++)
{ for(j=c1;j<=c2;j++)
{ v=(vid+i*160+j*2);
*v=*(buff+k);
k++;
v++;
*v=*(buff+k);
k++;
}
}
free(buff);
}/*End restorememory*/
//---------------------------------------------------------------------------
savefile()
{ FILE *fp;
int i,j;
//char *str="c:\\tc\\ex1";
fp=fopen(str,"w");
if(fp==NULL)
{ return;
}
i=0;
j=track[0];
while(j= { fputc(a[j],fp);
j++;
if(j==track[i+1])
{ fputc('\n',fp);
i++;
}
}
fputc('\n',fp);
fclose(fp);
}
//------------------------------------------------------------------------
saveasfile()
{ FILE *fp;
int i,j,r1,c1;
char *buff;
buff=savemem(8,18,16,58,buff);
drawbox(8,18,16,58,120);
doubleborder(8,18,16,58,127);
drawbox(10,21,10,55,16);
setcuserpos(10,21);
gets(str);
restoremem(8,18,16,58,buff);
fp=fopen(str,"w");
if(fp==NULL)
{ return;
}
i=0;
j=0;
while(j= { fputc(a[j],fp);
j++;
if(j==track[i+1])
{ fputc('\n',fp);
i++;
}
}
fputc('\n',fp);
fclose(fp);
}
//------------------------------------------------------------------------
openfile()
{ FILE *fp;
int i,j,r1,c1;
char *buff,ch;
buff=savemem(8,18,16,58,buff);
drawbox(8,18,16,58,120);
doubleborder(8,18,16,58,127);
drawbox(10,21,10,55,16);
setcuserpos(10,21);
gets(str);
restoremem(8,18,16,58,buff);
//writestring(str,31,1,30);
fp=fopen(str,"r");
p=0;
t=0;
track[0]=0;
while(!feof(fp))
{ ch=fgetc(fp);
if(ch!='\n')
{ a[p]=ch;
p++;
}
else
{ track[t+1]=p;
t++;
}
}
fclose(fp);
fp=1;
lp=21;
cl=1;
display();
}
//------------------------------------------------------------------------
/*This function opens the filemenu*/
int Filemenu(char *buff)
{ int i,sc,ac,c,r,r1,c1,flag;
char *s[]={"New","Open","Save","Save as","Close","Print","Exit"};
char *s1[]={"Create a new file",
"Load an existing file from the disk",
"Save current file",
"Save current file with new name",
"Close current file",
"Prints currently loaded file to printer",
"Exit the editor"
};
union REGS inregs,outregs;
setcursersize(32,10); /*Hides the curser*/
buff=savemem(1,1,12,20,buff);
drawbox(1,1,11,18,120);
drawbox(2,19,12,20,7);
drawbox(12,3,12,18,7);
drawborder(1,2,11,17,112);
r=2; c=4;
for(i=0;i=<7;i++)
{ writestring(s[i],112,r,c);
r++;
if(i==4)
{ drawline(r,2,17,112);
r++;
}
if(i==5)
{ drawline(r,2,17,112);
r++;
}
}
sc=72; flag=2;
while(1)
{ if(sc==72) /*Up arrow*/
{ if(flag==1)
flag=7;
else
flag--;
}
else /*Down arrow*/
{ if(sc==80)
{ if(flag==7)
flag=1;
else
flag++;
}
else
flag=8; /*Right or Left arrow*/
}
switch(flag)
{ case 1:
drawbox(2,3,2,16,32);
writestring(s[0],32,2,4);
r=2; i=0;
writestring(s1[0],112,24,1);
break;
case 2:
drawbox(3,3,3,16,32);
writestring(s[1],32,3,4);
r=3; i=1;
writestring(s1[1],112,24,1);
break;
case 3:
drawbox(4,3,4,16,32);
writestring(s[2],32,4,4);
r=4; i=2;
writestring(s1[2],112,24,1);
break;
case 4:
drawbox(5,3,5,16,32);
writestring(s[3],32,5,4);
r=5; i=3;
writestring(s1[3],112,24,1);
break;
case 5:
drawbox(6,3,6,16,32);
writestring(s[4],32,6,4);
r=6; i=4;
writestring(s1[4],112,24,1);
break;
case 6:
drawbox(8,3,8,16,32);
writestring(s[5],32,8,4);
r=8; i=5;
writestring(s1[5],112,24,1);
break;
case 7:
drawbox(10,3,10,16,32);
writestring(s[6],32,10,4);
r=10; i=6;
writestring(s1[6],112,24,1);
break;
case 8:
if(sc==77) /*Right arrow return */
{ restoremem(1,1,12,20,buff); /*Scancode of Editmenu*/
return(18);
}
else
{ if(sc==75)
{ restoremem(1,1,12,20,buff); /*Left arrow return*/
/*Scancode of Helpmenu*/
return(35);
}
else
{ restoremem(1,1,12,20,buff);/*Return & Escape*/
return(sc);
}
}
}
getcharacter(&sc,&ac);
drawbox(r,3,r,16,112);
writestring(s[i],112,r,4);
drawbox(24,1,24,55,112);
if(ac==13)
{ switch(r)
{ case 2: restoremem(1,1,12,20,buff);
refreshscreen();
setcuserpos(2,1);
fp=1;
cl=1;
t=0;
lp=21;
p=0;
return(1);
case 3: readcurser(&r1,&c1);
restoremem(1,1,12,20,buff);
openfile();
setcuserpos(r1,c1);
return(1);
case 4: readcurser(&r1,&c1);
restoremem(1,1,12,20,buff);
savefile();
setcuserpos(r1,c1);
return(1);
case 5: readcurser(&r1,&c1);
restoremem(1,1,12,20,buff);
saveasfile();
setcuserpos(r1,c1);
return(1);
case 6:
case 8:
case 10:
return(0);
} }
}
}/*End filemenu*/
//-------------------------------------------------------------------------
/*This function opens the Editmenu*/
int Editmenu(char *buff)
{ int i,sc,ac,r,c,flag;
char *s[]={"Cut Ctrl+X","Copy Ctrl+C","Paste Ctrl+V","Clear Del"};
char *s1[]={"Delete selected text and copies it to buffer",
"Copies selected text to buffer",
"Insert buffer contents at current location",
"Delete selected text without copying it to buffer"
};
union REGS inregs,outregs;
setcursersize(32,10); /*Hide the cursor*/
buff=savemem(1,8,7,28,buff);
drawbox(1,8,6,26,120);
drawbox(2,27,7,28,7);
drawbox(7,10,7,26,7);
drawborder(1,9,6,25,112);
r=2; c=11;
for(i=0;i<4;i++)
{ writestring(s[i],112,r,c);
r++;
}
sc=72; flag=2;
while(1)
{ if(sc==72) /*Up arrow*/
{ if(flag==1)
flag=4;
else
flag--;
}
else
{ if(sc==80) /*Down arrow*/
{ if(flag==4)
flag=1;
else
flag++;
}
else
flag=5; /*Right or Left arrow*/
}
switch(flag)
{ case 1:
drawbox(2,10,2,24,32);
writestring(s[0],32,2,11);
r=2; i=0;
writestring(s1[0],112,24,1);
break;
case 2:
drawbox(3,10,3,24,32);
writestring(s[1],32,3,11);
r=3; i=1;
writestring(s1[1],112,24,1);
break;
case 3:
drawbox(4,10,4,24,32);
writestring(s[2],32,4,11);
r=4; i=2;
writestring(s1[2],112,24,1);
break;
case 4:
drawbox(5,10,5,24,32);
writestring(s[3],32,5,11);
r=5; i=3;
writestring(s1[3],112,24,1);
break;
case 5:
if(sc==77) /*Right arrow return */
{ restoremem(1,8,7,28,buff); /*Scancode of Searchmenu*/
return(31);
}
else
{ if(sc==75)
{ restoremem(1,8,7,28,buff);/*Left arrow return */
return(33); /*Scancode of Filemenu*/
}
else
{ restoremem(1,8,7,28,buff);
return(sc); /*Return & Escape*/
}
}
}
getcharacter(&sc,&ac);
drawbox(r,10,r,24,112);
writestring(s[i],112,r,11);
drawbox(24,1,24,55,112);
}
}/*End Editmenu*/
//------------------------------------------------------------------------
/*This function opens the Searchmenu*/
int Searchmenu(char *buff)
{ int i,sc,ac,r,c,flag;
char *s[]={ "Find",
"Repeat Last Find F3",
"Replace"
};
char *s1[]={"Find specified text",
"Find next occurence of text specified in previous search",
"Finds and changes specified text"
};
union REGS inregs,outregs;
setcursersize(32,10); /*Hide the cursor*/
buff=savemem(1,14,6,44,buff);
drawbox(1,14,5,42,120);
drawbox(2,43,6,44,7);
drawbox(6,16,6,42,7);
drawborder(1,15,5,41,112);
r=2; c=17;
for(i=0;i<3;i++)
{ writestring(s[i],112,r,c);
r++;
}
sc=72; flag=2;
while(1)
{ if(sc==72) /*Up arrow*/
{ if(flag==1)
flag=3;
else
flag--;
}
else
{ if(sc==80) /*Down arrow*/
{ if(flag==3)
flag=1;
else
flag++;
}
else
flag=4; /*Right or Left arrow*/
}
switch(flag)
{ case 1:
drawbox(2,16,2,40,32);
writestring(s[0],32,2,17);
r=2; i=0;
writestring(s1[0],112,24,1);
break;
case 2:
drawbox(3,16,3,40,32);
writestring(s[1],32,3,17);
r=3; i=1;
writestring(s1[1],112,24,1);
break;
case 3:
drawbox(4,16,4,40,32);
writestring(s[2],32,4,17);
r=4; i=2;
writestring(s1[2],112,24,1);
break;
case 4:
if(sc==77)
{ restoremem(1,14,6,44,buff); /*Right arrow return*/
return(47); /*Scancode of Viewmenu*/
}
else
{ if(sc==75)
{ restoremem(1,14,6,44,buff);/*Left arrow return*/
return(18); /*Scancode of Editmenu*/
}
else
{ restoremem(1,14,6,44,buff);
return(sc); /*Return & Escape*/
}
}
}
getcharacter(&sc,&ac);
drawbox(r,16,r,40,112);
writestring(s[i],112,r,17);
drawbox(24,1,24,56,112);
}
}/*End Searchmenu*/
//------------------------------------------------------------------------
/*This function opens the Viewmenu*/
int Viewmenu(char *buff)
{ int i,sc,ac,r,c,flag;
char *s[]={ "Split Window Ctrl+F6",
"Size Window Ctrl+F8",
"Close Window Ctrl+F4",
"1 UNTITLED Alt+1"
};
char *s1[]={"Open a second edit window",
"Resize the edit window",
"Close the second edit window",
"Selects a file to view"
};
union REGS inregs,outregs;
setcursersize(32,10); /*Hide the cursor*/
buff=savemem(1,22,8,47,buff);
drawbox(1,22,7,45,120);
drawbox(2,46,8,47,7);
drawbox(8,24,8,45,7);
drawborder(1,23,7,44,112);
r=2; c=24;
for(i=0;i<4;i++)
{ writestring(s[i],112,r,c);
r++;
if(i==2)
{ drawline(r,23,44,112);
r++;
}
}
sc=72; flag=2;
while(1)
{ if(sc==72) /*Up arrow*/
{ if(flag==1)
flag=4;
else
flag--;
}
else
{ if(sc==80) /*Down arrow*/
{ if(flag==4)
flag=1;
else
flag++;
}
else
flag=5; /*Right or Left arrow*/
}
switch(flag)
{ case 1:
drawbox(2,24,2,43,32);
writestring(s[0],32,2,24);
r=2; i=0;
writestring(s1[0],112,24,1);
break;
case 2:
drawbox(3,24,3,43,32);
writestring(s[1],32,3,24);
r=3; i=1;
writestring(s1[1],112,24,1);
break;
case 3:
drawbox(4,24,4,43,32);
writestring(s[2],32,4,24);
r=4; i=2;
writestring(s1[2],112,24,1);
break;
case 4:
drawbox(6,24,6,43,32);
writestring(s[3],32,6,24);
r=6; i=3;
writestring(s1[3],112,24,1);
break;
case 5:
if(sc==77)
{ restoremem(1,22,8,47,buff); /*Right arrow return*/
return(24); /*Scancode of Optionmenu*/
}
else
{ if(sc==75)
{ restoremem(1,22,8,47,buff); /*Left arrow return*/
return(31); /*Scancode of Searchmenu*/
}
else
{ restoremem(1,22,8,47,buff);
return(sc); /*Return & Escape*/
}
}
}
getcharacter(&sc,&ac);
drawbox(r,24,r,43,112);
writestring(s[i],112,r,24);
drawbox(24,1,24,55,112);
}
}/*End Viewmenu*/
//-----------------------------------------------------------------------
/*This function opens the Optionmenu*/
int Optionmenu(char *buff)
{ int i,sc,ac,r,c,flag;
char *s[]={"Settings","About"};
char *s1[]={"Change editor setting",
"Change editor screen color"
};
union REGS inregs,outregs;
setcursersize(32,10); /*Hide the cursor*/
buff=savemem(1,28,5,46,buff);
drawbox(1,28,4,44,120);
drawbox(2,45,5,46,7);
drawbox(5,30,5,44,7);
drawborder(1,29,4,43,112);
r=2; c=31;
for(i=0;i<2;i++)
{ writestring(s[i],112,r,31);
r++;
}
sc=72; flag=2;
while(1)
{ if(sc==72) /*Up arrow*/
{ if(flag==1)
flag=2;
else
flag--;
}
else
{ if(sc==80) /*Down arrow*/
{ if(flag==2)
flag=1;
else
flag++;
}
else
flag=3; /*Right or Left arrow*/
}
switch(flag)
{ case 1:
drawbox(2,30,2,42,32);
writestring(s[0],32,2,31);
r=2; i=0;
writestring(s1[0],112,24,1);
break;
case 2:
drawbox(3,30,3,42,32);
writestring(s[1],32,3,31);
r=3; i=1;
writestring(s1[1],112,24,1);
break;
case 3:
if(sc==77)
{ restoremem(1,28,5,46,buff); /*Right arrow return*/
return(35); /*Scancode of Helpmenu*/
}
else
{ if(sc==75)
{ restoremem(1,28,5,46,buff);/*Left arrow return*/
return(47); /*Scancode of Viewmenu*/
}
else
{ restoremem(1,28,5,46,buff);
return(sc); /*Return & Escape*/
}
}
}
getcharacter(&sc,&ac);
drawbox(r,30,r,42,112);
writestring(s[i],112,r,31);
drawbox(24,1,24,55,112);
}
}/*End Optionmenu*/
//------------------------------------------------------------------------
/*This function opens the Helpmenu*/
int Helpmenu(char *buff)
{ int i,sc,ac,r,c,flag;
char *s[]={"Commands","About"};
char *s1[]={"Help on edit commands",
"About help"
};
union REGS inregs,outregs;
setcursersize(32,10); /*Hide the cursor*/
buff=savemem(1,36,5,52,buff);
drawbox(1,36,4,50,120);
drawbox(1,51,5,52,7);
drawbox(5,36,5,50,7);
drawborder(1,37,4,49,112);
r=2; c=39;
for(i=0;i<2;i++)
{ writestring(s[i],112,r,c);
r++;
}
sc=72; flag=2;
while(1)
{ if(sc==72) /*Up arrow*/
{ if(flag==1)
flag=2;
else
flag--;
}
else
{ if(sc==80) /*Down arrow*/
{ if(flag==2)
flag=1;
else
flag++;
}
else
flag=3; /*Right or left arrow*/
}
switch(flag)
{ case 1:
drawbox(2,38,2,48,32);
writestring(s[0],32,2,39);
r=2; i=0;
writestring(s1[0],112,24,1);
break;
case 2:
drawbox(3,38,3,48,32);
writestring(s[1],32,3,39);
r=3; i=1;
writestring(s1[1],112,24,1);
break;
case 3:
if(sc==77)
{ restoremem(1,36,5,52,buff);/*Right arrow return*/
return(33); /*Scancode of Filemenu*/
}
else
{ if(sc==75)
{ restoremem(1,36,5,52,buff);/*Left arrow return*/
return(24); /*Scancode of Optionmenu*/
}
else
{ restoremem(1,36,5,52,buff);
return(sc); /*Return & Escape*/
}
}
}
getcharacter(&sc,&ac);
drawbox(r,38,r,48,112);
writestring(s[i],112,r,39);
drawbox(24,1,24,55,112);
}
}/*End Helpmenu*/
//-----------------------------------------------------------------------
/*This function is used to hides the curser*/
setcursersize(int x,int y)
{ union REGS inregs,outregs;
inregs.h.ah=0x01;
inregs.h.ch=x;
inregs.h.cl=y;
int86(0x10,&inregs,&outregs);
}/*End setcurser*/
//------------------------------------------------------------------------
/*This function sets the cursor at given position*/
setcuserpos(int a,int b)
{ union REGS inregs,outregs;
inregs.h.ah=0x02;
inregs.h.bh=0;
inregs.h.dh=a;
inregs.h.dl=b;
int86(0x10,&inregs,&outregs);
}/*End setcurserpos*/
//-------------------------------------------------------------------------
/*This function is used to read current position of curser*/
readcurser(int *p1,int *p2)
{
union REGS inregs,outregs;
inregs.h.ah=0x03;
inregs.h.bh=0;
int86(0x10,&inregs,&outregs);
*p1=outregs.h.dh;
*p2=outregs.h.dl;
}/*End readcurser*/
//------------------------------------------------------------------------
getcharacter(int *p1,int *p2)
{ union REGS inregs,outregs;
inregs.h.ah=0;
int86(0x16,&inregs,&outregs);
*p1=outregs.h.ah;
*p2=outregs.h.al;
}
//------------------------------------------------------------------------
display()
{ int i,j,c=1,k=2,m;
refreshscreen();
for(i=fp-1;i<=t;i++)
{ if(i==lp)
break;
for(j=track[i]+eat; j { if(j>=track[i+1] && i!=t)
break;
if(a[j]==9)
{ for(m=0;m<8;m++)
writechar(32,23,k,c);
}
else
{
writechar(a[j],23,k,c);
}
c++;
}
c=1;
k++;
}
}
//-------------------------------------------------------------------------
delete1(int temp)
{ int i;
memmove(a+temp,a+(temp+1),1000-(temp+1));
p--;
for(i=cl;i<=t;i++)
track[i]=track[i]-1;
display();
}
//------------------------------------------------------------------------
insert(int temp,int ac)
{ int i;
memmove(a+(temp+1),a+temp,1000-temp);
p++;
*(a+temp)=ac;
for(i=cl;i<=t;i++)
track[i]=track[i]+1;
}
//-------------------------------------------------------------------------
activescreen(int sc,int ac,int *r,int *c)
{ int r1,c1,k,temp,i;
readcurser(&r1,&c1);
switch(sc)
{ case 71: if(eat!=0)
{ eat=0;
display();
}
readcurser(&r1,&c1);
c1=1;
setcuserpos(r1,c1);
break;
case 79: if(t!=(cl-1))
{ readcurser(&r1,&c1);
c1=track[cl]-track[cl-1]+1;
if(c1<78)
{ if(eat!=0)
{ eat=0;
display();
}
setcuserpos(r1,c1);
}
else
{ eat=c1-78;
display();
readcurser(&r1,&c1);
c1=78;
setcuserpos(r1,c1);
}
}
else
{ readcurser(&r1,&c1);
c1=p-track[cl-1]+1;
if(c1<78)
setcuserpos(r1,c1);
else
{ eat=c1-78;
display();
readcurser(&r1,&c1);
c1=78;
setcuserpos(r1,c1);
}
}
break;
case 73: if(fp!=1)
{ if(lp>41)
{ fp=fp-20;
lp=lp-20;
cl=cl-20;
display();
}
else
{ fp=1;
lp=21;
display();
readcurser(&r1,&c1);
cl=r1-1;
}
}
break;
case 81: if((fp+20){ fp=fp+20;
lp=lp+20;
cl=cl+20;
display();
if((lp-1)>t)
{ cl=t+1;
readcurser(&r1,&c1);
r1=cl-fp+2;
setcuserpos(r1,c1);
}
}
break;
case 83: if((cl-1)==t || (track[cl-1]+(c1+eat))<=track[cl])
{ readcurser(&r1,&c1);
temp=track[cl-1]+(c1+eat)-1;
delete1(temp);
}
else
{ temp=track[cl-1]+(c1+eat)-track[cl]-1;
k=temp+track[cl];
for(i=track[cl];iinsert(i,32);
memmove(track+cl,track+(cl+1),99-(cl+1));
t--;
display();
}
break;
case 14: readcurser(&r1,&c1);
temp=track[cl-1]+c1-2;
delete1(temp);
c1=c1-1;
setcuserpos(r1,c1);
break;
case 15: a[p]=ac;
p++;
writechar(ac,23,r1,c1);
c=c1+8;
break;
case 72: if(cl!=1)
{ if(cl>fp)
{ cl--;
readcurser(&r1,&c1);
r1--;
setcuserpos(r1,c1);
}
else
{ fp--;
lp--;
cl--;
display();
// setcuserpos(r1,c1);
}
}
break;
case 80: if(cl!=t+1)
{ if(cl{ cl++;
readcurser(&r1,&c1);
r1++;
setcuserpos(r1,c1);
}
else
{ fp++;
lp++;
cl++;
display();
}
}
break;
case 77: if(c1<78)
{ c1++;
setcuserpos(r1,c1);
}
else
{ eat++;
display();
}
break;
case 75: if(c1!=1)
{ if((eat+c1)>78)
{ eat--;
display();
}
else
{ c1--;
setcuserpos(r1,c1);
}
}
break;
default: if(track[cl-1]+c1-1+eat==p)
{ if(ac==13)
{ t++;
track[t]=track[t-1]+(eat+c1)-1;
k=t;
t--;
if(cl==lp)
{ fp++;
lp++;
display();
readcurser(&r1,&c1);
c1=1;
setcuserpos(r1,c1);
}
cl++;
if(eat!=0)
{ eat=0;
display();
}
t=k;
if(lp<=21)
{ readcurser(&r1,&c1);
r1=r1+1;
c1=1;
setcuserpos(r1,c1);
}
}
else
{ if((eat+c1)>= 78)
{ a[p]=ac;
eat++;
setcuserpos(r1,78);
display();
p++;
}
else
{ writechar(ac,23,r1,c1);
a[p]=ac;
p++;
c1++;
setcuserpos(r1,c1);
}
}
}
else
{ readcurser(&r1,&c1);
if((track[cl-1]+c1+eat)>track[cl])
{ readcurser(&r1,&c1);
temp=track[cl-1]+(c1+eat)-1;
for(i=track[cl];iinsert(i,32);
}
if(ac!=13)
{ readcurser(&r1,&c1);
if(eat==0)
{ temp=track[cl-1]+c1-1;
insert(temp,ac);
display();
c1=c1+1;
setcuserpos(r1,c1);
}
else
{ temp=track[cl-1]+(c1+eat)-1;
insert(temp,ac);
eat++;
display();
c1=78;
setcuserpos(r1,c1);
}
}
else
{ memmove(track+(cl+1),track+cl,99-cl);
*(track+cl)=track[cl-1]+(c1+eat)-1;
t++;
r1=r1+1;
c1=1;
display();
setcuserpos(r1,c1);
cl++;
}
}
}
*r=r1;
*c=c1;
}
main()
{ int i,r,c,sc,c1,ac,k,m,exit=0;
union REGS inregs,outregs;
char far *v;
char *buff,*s[]= { "File",
"Edit",
"Search",
"View",
"Option",
"Help",
"Line:",
"Col:"
};
clrscr();
drawscreen();
track[t]=0;
c=3;
writestring(s[0],112,0,c); /*String,Attribute,Row No,Column No*/
c=9;
writestring(s[1],112,0,c);
c=15;
writestring(s[2],112,0,c);
c=23;
writestring(s[3],112,0,c);
c=29;
writestring(s[4],112,0,c);
c=37;
writestring(s[5],112,0,c);
writechar(179,112,24,58);
writestring(s[6],112,24,61);
writestring(s[7],112,24,70);
c=1; r=2;
setcuserpos(2,1);
while(!exit)
{ m=77;
drawbox(24,75,24,77,120);
c1=eat+c;
while(c1>0)
{ k=c1%10;
writechar(k+48,112,24,m);
c1=c1/10;
m--;
}
m=69;
r=cl;
drawbox(24,66,24,69,120);
while(r>0)
{ k=r%10;
writechar(k+48,112,24,m);
r=r/10;
m--;
}
getcharacter(&sc,&ac);
while(sc!=1 && ac==0 && sc!=77 && sc!=75 && sc!=72 && sc!=15 && sc!=80 && sc!=71 && sc!=79 && sc!=73 && sc!=81 && sc!=83 && sc!=14)
{ switch(sc)
{ case 33: writestring(s[0],32,0,3);
sc = Filemenu(buff);
if(sc==0)
exit=1;
writestring(s[0],112,0,3);
break;
case 18: writestring(s[1],32,0,9);
sc = Editmenu(buff);
writestring(s[1],112,0,9);
break;
case 31: writestring(s[2],32,0,15);
sc = Searchmenu(buff);
writestring(s[2],112,0,15);
break;
case 47: writestring(s[3],32,0,23);
sc = Viewmenu(buff);
writestring(s[3],112,0,23);
break;
case 24: writestring(s[4],32,0,29);
sc = Optionmenu(buff);
writestring(s[4],112,0,29);
break;
case 35: writestring(s[5],32,0,37);
sc = Helpmenu(buff);
writestring(s[5],112,0,37);
break;
default:
sc=1;
}
setcursersize(5,6);
}
if(sc!=1)
activescreen(sc,ac,&r,&c);
}
}
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History Of C..
In the beginning was Charles Babbage and his Analytical Engine, a machine
he built in 1822 that could be programmed to carry out different computations.
Move forward more than 100 years, where the U.S. government in
1942 used concepts from Babbage’s engine to create the ENIAC, the first
modern computer.
Meanwhile, over at the AT&T Bell Labs, in 1972 Dennis Ritchie was working
with two languages: B (for Bell) and BCPL (Basic Combined Programming
Language). Inspired by Pascal, Mr. Ritchie developed the C programming
language.
he built in 1822 that could be programmed to carry out different computations.
Move forward more than 100 years, where the U.S. government in
1942 used concepts from Babbage’s engine to create the ENIAC, the first
modern computer.
Meanwhile, over at the AT&T Bell Labs, in 1972 Dennis Ritchie was working
with two languages: B (for Bell) and BCPL (Basic Combined Programming
Language). Inspired by Pascal, Mr. Ritchie developed the C programming
language.
My 1st Program...
#include
#include
void main ()
{
clrscr ();
printf ("\n\n\n\n");
printf ("\t\t\t\"Life is Good...\"\n");
printf ("\t\t\t********************************");
getch ();
}
Next Step...
#include
#include
void main ()
{
clrscr ();
printf ("\n\n\n\n\n\n\n\n");
printf ("\t\t\t --------------------------- \n\n");
printf ("\t\t\t | IGCT, Info Computers, INDIA | \n\n");
printf ("\t\t\t --------------------------- ");
}